03 Jul Aurora Saturday 18:00 Python Homework 20.06.27.
Question:
Continue to program the code we made in the class at the bottom of this page. Try to use for loop to create buttons from 1-9, so the tkinter window would display as below:
Hint:
You can use “for i in range(1, 10):” or “for i in ‘123456789’:” to build these 9 buttons, however, you should thinking of how to use math techniques to solve the row and column.
for example, buttons 1,2,3 are in row 1 and buttons 4,5,6 are in row 2. You should think that int(1/3) is 0 or 1//3 is 0, 2//3 is still 0, 3//3 is 1, 4//3 is 1, 5//3 is 1, 6//3 is 2. Then how can you make 1,2,3 all become 1, while 4,5,6 all become 2?
You should use %(finding division remainder) to solve columns, but how?
You can finish the code below:
from tkinter import * class Calculator: def __init__(self, master): self.master = master self.master.title('Calculator') self.f1 = Frame(self.master) self.f1.option_add('*Font', 'arial 30 bold') self.f1.pack(expand=YES, fill=BOTH) self.strDisplay = StringVar() self.strDisplay.set('0') self.lblDisplay = Label(self.f1, textvariable=self.strDisplay, justify='right') self.lblDisplay.pack(side=RIGHT) self.f2 = Frame(self.master) self.f2.option_add('*Font', 'arial 16') self.f2.pack(expand=YES, fill=BOTH) self.btnCE = Button(self.f2, text='CE', bg='#f8f8f8', width=4, command=self.reset, bd=1) self.btnCE.grid(row=0, column=0) self.btnRecip = Button(self.f2, text='1/x', bg='#f8f8f8', width=4, command=self.recip, bd=1) self.btnRecip.grid(row=0, column=1) self.btnBack = Button(self.f2, text='<-', bg='#f8f8f8', width=4, command=self.back, bd=1) self.btnBack.grid(row=0, column=2) for i in range(1, 10): btnNum = Button(self.f2, text=______, bg='#f8f8f8', width=4, bd=1) btnNum.grid(row=________, column=__________) def back(self): pass def reset(self): pass def recip(self): pass tk = Tk() myCal = Calculator(tk) tk.mainloop()
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